Calculate Peukert correction
Computes runtime and effective capacity at the actual discharge current. For LiFePO₄ the correction is switched off and explained, rather than applying an effect that does not exist there. It also converts between capacity rating hours — C20 against C5.
The formulas behind the calculator
Every number above can be recomputed: the full calculation path, all assumptions and the data source with retrieval date — plus cross-validation against independent references. Disclosed, not claimed.
An estimate based on the stated assumptions. The final design must be checked by a qualified professional against the rules that apply where you are.
Data as of: 2026-06-15
| Step | Formula | Value | Provenance |
|---|---|---|---|
| Peukert exponent | k | 1.25 | assumed |
| Discharge time per Peukert | H * (C_H / (H * I))^k | 8.409 h | exact |
| Effective capacity | C_H * ((C_H / H) / I)^(k-1) | 84.09 Ah | exact |
| Capacity rating conversion | C_H1 * (H2 / H1)^((k-1)/k) | 75.786 Ah | exact |
- Formula
t = H · (C_H / (H · I))^k · C_eff = C_H · ((C_H / H) / I)^(k−1)- Valid for
- Constant discharge per Peukert (t = H·(C/(H·I))^k), capacity stated with a named reference rate. Without a datasheet value the chemistry’s band midpoint applies — visibly as an assumption; for LiFePO4/NMC the correction is switched off with an explanation. Reference case: 100 Ah C20, 10 A, flooded → 8.41 h instead of a linear 10 h (−15.9 %), converted to C5: 75.8 Ah.
- Not covered
- Charging, strongly fluctuating loads (approximation via effective current), temperature influence on the exponent, recovery during load pauses, ageing. Inrush peaks are checked by calculator 35, mixed profiles by calculator 7.
- Data sources
- Manufacturer datasheets (Victron, Fronius, BYD) and IEC 61427-1, aggregated · retrieved 2026-06-15
Frequently asked questions
How long will my 100 Ah lead-acid battery really last at a 10 A draw?
Less than the rating suggests: with the Peukert formula t = H · (C_H / (H · I))^k, the reference case (C20 = 100 Ah, 10 A, k = 1.25) gives about 8.4 hours instead of 10, an effective capacity of roughly 84 Ah. The Peukert exponent should come from your datasheet — if it is missing, the calculator uses the chemistry's typical range and marks it as an assumption.
Does the Peukert effect apply to LiFePO4 batteries?
Effectively no: for LiFePO4 the exponent sits around 1.00 to 1.05, so the effect is negligible. The calculator switches the correction off for lithium and tells you why, instead of computing an effect that does not exist there. This avoids both common mistakes — applying Peukert to lithium (too pessimistic) and skipping it for lead (too optimistic).
Does the Peukert calculation hold for a cycling fridge or inverter surges?
No — it is valid only for a constant discharge current with the battery at rated temperature. Strongly varying loads such as fridge cycling or inverter surges, temperature effects and ageing are outside the model, and discharges faster than the one-hour rate fall outside the range where the approximation is established for lead.
How large is the Peukert effect in the reference case, concretely?
A 100 Ah lead battery (C20, k = 1.25) delivers not 10 hours at 10 A but t = 20 · (100/200)^1.25 = 8.41 hours — effectively 84.1 Ah instead of 100. The naive C/I calculation overestimates runtime by 19%. At higher currents the error grows: at 50 A only about 56 Ah of the 100 Ah remain.
Why are “100 Ah at C20” and “100 Ah at C5” not the same battery?
Because the capacity figure depends on the discharge duration: C20 means “measured over a 20-hour discharge” (5 A), C5 over five hours (20 A). The same physical lead battery shows markedly fewer amp-hours at C5 than at C20 — about 24% fewer at k = 1.25. A manufacturer stating “100 Ah at C5” therefore sells a larger battery than one stating “100 Ah at C20”. The converter makes both comparable; this is the most common hidden comparison error when buying lead batteries.
Does Peukert apply to LiFePO₄ as well?
Practically not: k is around 1.00–1.05 for lithium chemistries, and usable capacity is nearly independent of discharge current — one of the real advantages over lead. The calculator then deliberately applies no correction, reports PEUKERT_NEGLIGIBLE and explains why. In the curve chart, ideal line and curve visibly coincide.
Where does the Peukert exponent come from if I don't enter one?
From the chosen chemistry's band midpoint: flooded 1.25 (band 1.2–1.3), AGM 1.10 (1.05–1.15), gel 1.15 — and the page shows this visibly as the dominating assumption. The datasheet value remains the better number, via the switch in the advanced assumptions. Until 5 August 2026 the form silently sent 1.25 for every chemistry — for AGM that cost almost an hour of runtime in the reference case (8.41 instead of 9.33 h) and suppressed the warning.
How large is the Peukert loss in the reference case exactly?
100 Ah (C20) at 10 A discharge: instead of the linear 10 hours, 8.41 hours remain — effectively 84.1 Ah, a 15.9 % loss, because discharge runs at twice the reference current. The same battery converted to C5 carries only 75.8 Ah. Planning C5 loads against C20 capacity compares apples with oranges — which is exactly what the reference-rate converter beside it is for.
Why does the calculator switch Peukert off for LiFePO4?
Because the exponent there sits at 1.00 to 1.05 and the effect vanishes into noise: 100 Ah at 10 A remain practically 10.0 hours. Computing a “correction” that does not exist would be as wrong as omitting it for lead. The calculator explains the switch-off instead of hiding it — ruling out both common errors.
Does Peukert apply to charging or fluctuating loads?
No. The relation describes constant discharge; it does not act during charging, and under strongly fluctuating load the calculation is only an approximation via the effective current. Inrush and peak currents belong to the C-rate calculator, mixed daily profiles to the runtime calculator with its load scenarios.
Why does the reference duration (C20, C10, C5) matter at all?
Because “100 Ah” without a reference rate is an incomplete statement: the same lead battery rated 100 Ah at C20 delivers only about 76 Ah at C5. Manufacturers pick the rate that yields the biggest number. The calculator therefore requires the rate and converts to another on request — only then are two datasheets comparable.