Calculate voltage drop

Computes the voltage drop across a conductor size you already have, for DC as well as single- and three-phase AC. It also answers the three reverse questions: maximum length, maximum current, minimum cross-section.

  • The voltage drop is 7.47 %, above the 3 % limit under IEC 60364. Step up one cross-section or shorten the run.DROP_ABOVE_STANDARD

Input

Input
Circuit

One-way distance; the calculation uses out and return conductors.

Existing or planned cross-section — the calculator checks instead of recommending.

Your design limit. The code limit is checked additionally.

Result · Live

  • The voltage drop is 7.47 %, above the 3 % limit under IEC 60364. Step up one cross-section or shorten the run.DROP_ABOVE_STANDARD
Voltage drop
7.47%out and return conductors, temperature-corrected resistance
Voltage drop, absolute
0.90Vwhat is missing at the load
Power loss
26.9Wturns into heat in the cable
Annual loss in cents
968ct/athe price of the thin cable, every year
Headroom: maximum length
2.0mstill permissible at this cross-section and current
  • The voltage drop is 7.47 % and exceeds your target of 3 %. The next size up provides headroom.DROP_ABOVE_LIMIT
  • Conductor temperature is a default, not your input. Inside a conduit it runs considerably hotter, which increases the required size.TEMP_ASSUMED
  • Length is the one-way run. The factor of 2 for the return conductor is already in the formula.LENGTH_INTERPRETATION
  • This size satisfies voltage drop. Ampacity must be checked separately — 30 A is required.AMPACITY_SEPARATE_CHECK
The voltage drop against both limits
7.47 %your limit 3 %code limit 3 %actual

Yellow dashed is your design limit, red the code’s — the bar turns red once your limit is breached.

The three reverse questions
Maximum length at this cross-section and current: 2 mMaximum current at this length and cross-section: 12.1 AMinimum cross-section for length and current: 14.9 mm²

The same formula, solved three times for a different variable — the headroom you really want to know before laying the cable.

Calculation steps
  • Resistivity at conductor temperature: rho_20 * (1 + alpha * (T - 20)) = 0.017919 Ohm*mm^2/m
  • Actual voltage drop: (2 * rho * L * I) / A = 0.89593 V
  • Voltage drop in percent: dU / U_nom * 100 = 7.4661 %
  • Power lost in the conductor: dU * I = 26.878 W

The formulas behind the calculator

Every number above can be recomputed: the full calculation path, all assumptions and the data source with retrieval date — plus cross-validation against independent references. Disclosed, not claimed.

Safety-relevant calculation. This is an estimate based on the stated assumptions. The final design must be checked by a qualified electrician against the rules that apply where you are.

Data as of: 2026-07-15 · The technical review of this safety-relevant calculator is still outstanding.

Every intermediate value with its formula, number and provenance
StepFormulaValueProvenance
Resistivity at conductor temperaturerho_20 * (1 + alpha * (T - 20))0.017919 Ohm*mm^2/mmeasured
Actual voltage drop(2 * rho * L * I) / A0.89593 Vexact
Voltage drop in percentdU / U_nom * 1007.4661 %exact
Power lost in the conductordU * I26.878 Wexact
Formula
ΔU = 2 · ρ(T) · L · I / A · ΔU% = ΔU / U_nom · 100
Valid for
DC two-wire (factor 2), AC single- and three-phase (factor 2 or √3, ΔU via R′·cos φ + X′·sin φ); reactance from the NYY catalogue for the cross-section or as datasheet input — the engine never guesses it. References: 30 A/5 m/12 V in 6 mm² → 7.47 % (code violation against 3 % IEC — deliberately the example); 16 A/25 m/400 V three-phase in 2.5 mm² → 1.24 %. Reverse questions (max length/current, min cross-section) only in the DC case — not solvable in closed form for AC, stated openly.
Not covered
Ampacity (calculator 18), chains of several runs (calculator 14), harmonics, skin effect (negligible at 50 Hz and these sizes), inrush currents (the case covers continuous current).
Data sources
  • Official publications of the standards bodies and state authorities (NFPA, IEC, DKE/VDE, CEN) · retrieved 2026-07-15

Frequently asked questions

I already have 6 mm² cable — how do I check whether it is sufficient?

Unlike the wire-sizing calculator, the cross-section here is an input, not a result: the calculator returns the drop in volts and percent, the power loss, and a comparison against both your own limit and the applicable standard's limit. For the DC two-wire case it additionally answers the three reverse questions: maximum length, maximum current and minimum cross-section.

Why is the reactance per metre X′ a required input for AC circuits?

For AC the drop is ΔU = 2 (or √3) · I · L · (R′ · cos φ + X′ · sin φ), so the reactance term is mandatory. It is found in the cable datasheet, not in the standard, and varies by more than a factor of two depending on construction. Assuming a typical value would be exactly the kind of silent guess this engine refuses to make.

Does an acceptable voltage drop mean the cable is thermally safe?

No — this calculator checks voltage drop only. A cross-section can meet the drop limit and still be thermally impermissible; ampacity is a separate check, which the result explicitly flags. Harmonics, contact resistance at terminals and connectors, short-circuit withstand and skin effect at very large cross-sections are also outside the scope.

What distinguishes this calculator from the wire-size calculator?

The direction: the wire-size calculator recommends a size for given requirements; this one checks an EXISTING or planned run — and additionally answers the three reverse questions: how much longer may the run get at this cross-section, how much current does it carry, what cross-section would be minimal? That is the question you actually have on site with the cable drum in hand.

Why are two limits checked?

Your design limit (e.g. 3%) is a quality decision — for module-controller runs 1–2% often pays, since every point directly costs yield. The code limit is binding independently. The calculator shows both lines in the bar and warns separately: breaching your limit means inefficient, breaching the code limit means impermissible.

How much does conductor temperature distort the result?

Copper resistance rises ~0.4% per kelvin: between a 20 °C workshop measurement and 60 °C in a sun-exposed cable duct lie 16% more resistance — and thus 16% more voltage drop. The calculator corrects resistance to your conductor temperature; the 30 °C default is conservative indoors, too low for roof runs in summer.

Can the calculator also check AC circuits?

Yes — since 5 August 2026 through the interface too: single-phase (230 V) and three-phase (400 V), with power factor and reactance. The AC half previously existed only in the calculation core; the form had no switch for it. For three-phase the formula uses √3 instead of factor 2 — 16 A over 25 m in 2.5 mm² gives 1.24 %.

Where does the AC reactance come from?

From the NYY catalogue dataset for the chosen cross-section — sourced, not guessed, and named as a note. The engine itself deliberately refuses to guess it: it lives in the cable datasheet, not the standard, and varies by construction by more than a factor of two. If you have your datasheet, enter the value via the switch — it then wins.

Why does the worked example show a code violation?

Because that is exactly the calculator's question: “I have 6 mm² lying around — is that enough?” For 30 A over 5 m at 12 V the answer is no — 7.47 % against the permitted 3 %. An example that always “passes” would hide the calculator's warning side. The three reverse questions beside it show the ways out: shorter run, less current, or 16 mm².

What do the three reverse questions mean?

They solve the same equation for one variable each: how long may the run be at most? How much current does it take within the limit? What cross-section would be needed? For the DC two-wire case all three solve in closed form; in the AC case with reactance they are omitted, because the equation no longer solves for a single variable — the page says so openly.

What does the voltage drop really cost per year?

Loss power times operating hours times electricity price — both factors are adjustable since 5 August 2026. The 6 mm² example burns 27 W; at 1,000 operating hours and 31.1 ct that is about €8 a year, a continuous runner would exceed €70. Set against the extra cost of 16 mm², the thicker cable often pays for itself in the first year.